1 /*
2 * Licensed to the Apache Software Foundation (ASF) under one
3 * or more contributor license agreements. See the NOTICE file
4 * distributed with this work for additional information
5 * regarding copyright ownership. The ASF licenses this file
6 * to you under the Apache License, Version 2.0 (the
7 * "License"); you may not use this file except in compliance
8 * with the License. You may obtain a copy of the License at
9 *
10 * http://www.apache.org/licenses/LICENSE-2.0
11 *
12 * Unless required by applicable law or agreed to in writing, software
13 * distributed under the License is distributed on an "AS IS" BASIS,
14 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
15 * See the License for the specific language governing permissions and
16 * limitations under the License.
17 */
18
19 package org.apache.hadoop.hbase.util.byterange.impl;
20
21 import java.util.Collections;
22 import java.util.HashMap;
23 import java.util.List;
24
25 import org.apache.hadoop.hbase.classification.InterfaceAudience;
26 import org.apache.hadoop.hbase.util.ByteRange;
27 import org.apache.hadoop.hbase.util.CollectionUtils;
28 import org.apache.hadoop.hbase.util.IterableUtils;
29 import org.apache.hadoop.hbase.util.byterange.ByteRangeSet;
30
31 /**
32 * This is probably the best implementation of ByteRangeSet at the moment, though a HashMap produces
33 * garbage when adding a new element to it. We can probably create a tighter implementation without
34 * pointers or garbage.
35 */
36 @InterfaceAudience.Private
37 public class ByteRangeHashSet extends ByteRangeSet {
38
39 /************************ constructors *****************************/
40
41 public ByteRangeHashSet() {
42 this.uniqueIndexByUniqueRange = new HashMap<ByteRange, Integer>();
43 }
44
45 public ByteRangeHashSet(List<ByteRange> rawByteArrays) {
46 for (ByteRange in : IterableUtils.nullSafe(rawByteArrays)) {
47 add(in);
48 }
49 }
50
51 @Override
52 public void addToSortedRanges() {
53 sortedRanges.addAll(CollectionUtils.nullSafe(uniqueIndexByUniqueRange.keySet()));
54 Collections.sort(sortedRanges);
55 }
56
57 }